Solution 3 for Scaler Topics Fortnightly Contest - 4
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DSA Problem Solving for Interviews using Java
by Jitender Punia
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This article is part of the Scaler Topics Fortnightly Contest - 4.
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Solution Approach
- If you were working in real life what strategy you would have followed?
- You would have been greedy while carrying the plates.
- If you are at sink i, can you calculate how many plates would cross sink i?
- Let’s say finally ‘avg’ number of plates will be present in each sink When you are at sink i, if sum of plates till index ‘i’ is more than ‘avgi’ plates, then definitely those extra plates would go beyond and though the index i. That means at some point we will make ‘sum[1…i] - avgi’ moves.
- Similarly if sum[1…i] is less than ‘avgi’ plates, we will need ‘avgi - sum[1..i]’ plates, crossing index i.
- Therefore the answer is sum of abs(sum[1…i] - avg*i) for all the index.If you were working in real life what strategy you would have followed?
- You would have been greedy while carrying the plates. If you are at sink i, can you calculate how many plates would cross sink i?
- Let’s say finally ‘avg’ number of plates will be present in each sink. When you are at sink i, if sum of plates till index ‘i’ is more than ‘avgi’ plates, then definitely those extra plates would go beyond and though the index i. That means at some point we will make ‘sum[1…i] - avgi’ moves.
- Similarly if sum[1…i] is less than ‘avgi’ plates, we will need ‘avgi - sum[1..i]’ plates, crossing index i.
- Therefore the answer is sum of abs(sum[1…i] - avg*i) for all the index.
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