Solution 4 for Scaler Topics Fortnightly Contest - 11
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DSA Problem Solving for Interviews using Java
by Jitender Punia
1000
4.9
This article is part of the Scaler Topics Fortnightly Contest - 11
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Solution Approach
- Clearly we cannot apply normal Dijkstra algorithm here.
- We need to apply some modification of it.
- Let us suppose there are two paths one from B to z.
- Path 1: From B to x and then x to z, and
- Path 2: From B to y and then y to z.
- Suppose Both the paths are of equal weights.
- Then in our modified Dijkstra algorithm, we will pick the edge, which has
- Lesser weight of the last edge. (Proof is left as an exercise for the reader).
Time Complexity: O(Mlog(A)).
Space Complexity: O(A + M).
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