Solution 4 for Scaler Topics Fortnightly Contest - 16
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DSA Problem Solving for Interviews using Java
by Jitender Punia
1000
4.9
XOR Subsequence Complete Solution
This article is part of the Scaler Topics Fortnightly Contest - 16
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Solution Approach
- We will use this property of xor if = z then x = .
- We will divide the array in two parts let P1 and P2, then generate all the subsequences of each part.
- Now B if exist can be a subsequence of P1 or P2 or combination of some subsequence of both P1 and P2.
- First we will check if B exist in P1 or P2, if not then we will check for all subsequence P1 XOR B.
- If this xor value exists then we've found B as subsequence xor in A.
Time Complexity:- O Space Complexity:- O
C++ Implementation
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