Solution 2 for Scaler Topics Fortnightly Contest - 26
Bead Challenge
This article is part of the Scaler Topics Fortnightly Contest - 26
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To address this problem, the key approach involves breaking down all numbers in the array into their prime divisors. Following that, we calculate the frequency of each divisor by aggregating the decompositions of all numbers.
If each divisor appears exactly k⋅N times, where k is a natural number, it becomes feasible to make all numbers in the array equal. We can systematically apply the operation so that each number shares the same set of prime divisors.
However, if any divisor occurs a different number of times, achieving uniformity among the numbers in the array becomes impossible.
Time Complexity: O(NlogN) Space Complexity: O(NlogN)
C++ Implementation
Java Implementation
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