Solution 2 for Scaler Topics Fortnightly Contest - 28
Palindromifier
This article is part of the Scaler Topics Fortnightly Contest - 28
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We can just brute force on all the possible moves and check if the resulting string is a palindrome. There are a total of 2*(N-2) possible moves. We can check palindrome in O(N).
Time Complexity: O(N^2^) Space Complexity: O(N^2^)
C++ Implementation
Java Implementation
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