parseInt() in Java
FREE
The method parseInt() belongs to the Integer class which is under java.lang package. It is used to parse the string value as a signed decimal value. It is used in Java for converting a string value to an integer by using the method parseInt().
Syntax of parseInt() in Java
Following is how the parseInt() method can be declared in java:
Parameters of parseInt() in Java
| Data type | Parameter | Description |
|---|---|---|
| int | startIndex | It is the starting index of the string and is inclusive. |
| int | endIndex | It is the ending index of the string and is exclusive. |
| int | radix | It represents the base of the number in the string. |
| String | s | The string that is to be converted into an integer. |
| CharSequence | s | It is the sequence of characters that is to be converted to an integer. |
Transform Your Career
Choose from our industry-leading programs designed for career success
Modern Software and AI Engineering Program
Master full-stack development with AI integration
+1000 moreModern Data Science and ML with specialisation in AI
Advanced data science techniques with AI specialization
+1000 moreAdvanced AIML with Specialisation in Agentic AI
Deep dive into AIML with focus on Agentic systems
+1000 moreDevOps, Cloud & AI Platform Engineering
Build and manage AI-powered cloud infrastructure
+1000 moreAI Engineering Advanced Certification by IIT-Roorkee
Premier AI engineering certification from IIT-Roorkee
Return Values of parseInt() in Java
| Method name | Return |
|---|---|
| parseInt(String s) | Returns an integer value in its decimal equivalent |
| parseInt(String s, int radix) | Returns an integer value with base specified as radix. |
Note :
Radix is the parameter that specifies the number system to be used.
For example, binary = 2, octal = 8, hexadecimal = 16, etc.
Exceptions of parseInt() in Java
There are three types of exceptions possible by using the method parseInt() in java.
NullPointerException: It arises when the string s given as argument is null.
IndexOutOfBoundsException: It arises when:
- startIndex is negative
- startIndex > endIndex
- endIndex > s.length (length of given string)
NumberFormatException: It occurs when:
- CharSequence does not contain parsable int at a specified radix
- radix Character.MIN_RADIX
- radix Character.MAX_RADIX
Note:
Example of parseInt() in Java
Output:
More Examples
Example 1
Two strings are passed and are returned as their respective signed decimal Integer objects
Output:
Example 2
A user-defined example where anyone using this code can put a value of their choice and get the equivalent integer as output.
Output:
Explanation:
- Here, trim() is used to removed ending spaces from the left and right sides.
- These spaces otherwise, can cause NumberFormatException in Java.
Scaler Placement Report and Statistics
Scaler learners achieved 2.5x salary growth with average post-Scaler CTC reaching ₹23L.
Conclusion
- The method parseInt() belongs to the Integer class which is under java.lang package. It is used to parse the string value as a signed decimal value.
- Following are how the parseInt() method can be declared in java :
- public static int parseInt (String s).
- public static int parseInt (String s, int radix).
- public static int parseInt (CharSequence s, int startIndex, int endIndex, int radix).
- It is used in java for converting a string value to an integer by using the method parseInt().
- The parseInt() method throws three exceptions: NullPointerException, IndexOutOfBoundsException, NumberFormatException when the input arguments are not according to the conventions.
Google
Amazon
Microsoft
Flipkart
Adobe1200+ more